0=(p^2+6p-16)

Solution for 0=(p^2+6p-16) equation:

0=(p^2+6p-16)

We move all terms to the left:

0-((p^2+6p-16))=0

We add all the numbers together, and all the variables

-((p^2+6p-16))=0


We calculate terms in parentheses: -((p^2+6p-16)), so:

(p^2+6p-16)

We get rid of parentheses

p^2+6p-16

Back to the equation:

-(p^2+6p-16)


We get rid of parentheses

-p^2-6p+16=0

We add all the numbers together, and all the variables

-1p^2-6p+16=0

a = -1; b = -6; c = +16;
Δ = b2-4ac
Δ = -62-4·(-1)·16
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-10}{2*-1}=\frac{-4}{-2}
=+2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+10}{2*-1}=\frac{16}{-2}
=-8
$